What would be the mass of a bag of anhydrous magnesium sulfate, MgSO4, if it contained the same amount of magnesium as a 1.00kg bag of Epsom salts, MgSO4 x 7H2O? Give your answer in grams.
please help
1.00Kg x (molar mass MgSO4/molar mass MgSO4.7H2O) = ?? kg MgSO4.
To determine the mass of a bag of anhydrous magnesium sulfate, we need to compare it to the mass of a 1.00 kg bag of Epsom salts.
Epsom salts, MgSO4 x 7H2O, contains 7 molecules of water (H2O) for every one molecule of magnesium sulfate (MgSO4). The molar mass of water is 18.015 g/mol, and the molar mass of magnesium sulfate is 120.366 g/mol.
So, we first need to calculate the mass of water in the Epsom salts:
Mass of water = (7 moles of water) * (18.015 g/mol)
Next, we can calculate the mass of the magnesium sulfate in the Epsom salts:
Mass of magnesium sulfate = (1 mole of magnesium sulfate) * (120.366 g/mol)
Now, we'll subtract the mass of water from the total mass of the Epsom salts to find the mass of the anhydrous magnesium sulfate:
Mass of anhydrous magnesium sulfate = Mass of Epsom salts - Mass of water
Finally, we convert the mass from kilograms to grams to match the unit requested in the question.
Let's perform the calculations step by step:
1. Calculate the mass of water:
Mass of water = (7 moles of water) * (18.015 g/mol)
Mass of water = 126.105 g
2. Calculate the mass of magnesium sulfate:
Mass of magnesium sulfate = (1 mole of magnesium sulfate) * (120.366 g/mol)
Mass of magnesium sulfate = 120.366 g
3. Calculate the mass of anhydrous magnesium sulfate:
Mass of anhydrous magnesium sulfate = Mass of Epsom salts - Mass of water
Mass of anhydrous magnesium sulfate = 1000 g - 126.105 g
Mass of anhydrous magnesium sulfate = 873.895 g
Therefore, the mass of the bag of anhydrous magnesium sulfate would be 873.895 grams.