What is the new volume if the volume of a gas is 3.2 L when the temperature is 7 C if the temperature is increased to 15 C without changing the pressure
V1/T1=V2/T2
http://www.ausetute.com.au/charslaw.html
assuming the gas is ideal, we can use the formula,
V1/T1 = V2/T2
where
V1 = initial volume
T1 = initial temperature (in K)
V2 = final volume
T2 = final temperature (in K)
we first convert the given temp to Kelvin units:
T1 = 7 + 273.15 = 280.15 K
T2 = 15 + 273.15 = 288.15 K
substituting,
3.2 / 280.15 = (V2) / 288.15
V2 = 3.2 * 288.15 / 280.15
V2 = 3.29 L
hope this helps~ :)
To find the new volume of the gas, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (when pressure is constant). Here's how you can calculate it:
Step 1: Convert the temperatures to Kelvin.
Since Charles's Law requires temperature to be in Kelvin, we need to convert the given temperatures from Celsius to Kelvin. The Kelvin temperature scale is obtained by adding 273.15 to the Celsius temperature.
Initial temperature (in Kelvin): 7°C + 273.15 = 280.15 K
Final temperature (in Kelvin): 15°C + 273.15 = 288.15 K
Step 2: Set up the equation for Charles's Law.
Charles's Law can be written as V₁ / T₁ = V₂ / T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.
V₁ = 3.2 L (initial volume)
T₁ = 280.15 K (initial temperature)
T₂ = 288.15 K (final temperature)
V₂ is the volume we are trying to find.
Step 3: Solve the equation for V₂.
Using the values we have, we can rearrange the equation to solve for V₂:
V₁ / T₁ = V₂ / T₂
V₂ = (V₁ * T₂) / T₁
V₂ = (3.2 L * 288.15 K) / 280.15 K
Calculating this gives us:
V₂ ≈ 3.29 L
Therefore, the new volume of the gas when the temperature is increased to 15°C without changing the pressure is approximately 3.29 liters.