posted by Ryu .
For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the concentration of all species present, the pH, and the percent dissociation of a 0.29 M solution.
Propanoic acid = HPr
HPr ==> H^+ + Pr^-
Set up an ICE chart and substitute into the below equation.
Ka = (H^+)Pr^-)/(HPr)
Solve for (H^+) and convert to pH.
(Pr^-) = (H^+)
You can find OH^- from (H^+)(OH^-) = 1E-14
%diss = (H^+)/(HPr)*100 = ??