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business calculus

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find the slope of the tangent line
y= -5x^1/2 + X^3/2; X=25

  • business calculus -

    dy/dx = (-5/2)x^(-1/2) + (3/2)x^(1/2)
    = -5/(2√x) + 3√x/2
    when x = 25
    y = -5(√25) + (√25)^3 = -25 + 125 = 100
    dy/dx = -5/(2√25) + 3√25/2 = -1/2 + 15/2 = 7

    then
    (y-100) = 7(x-25)

    Finish it up to express the final equation is the form you want.

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