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158.5 mL of a AgNO3 solution at 5.0M was combined with a 3.5M CaCl2 solution. 110.5g of AgCl was recovered. Given that the CaCl2 is the limiting reagent, how many milliliters of the 3.5M CaCl2 solution was used?

  • Chemistry -

    Write the equation and balance it. Convert 110.5 g AgCl to moles AgCl, convert to moles CaCl2, then M = moles/L, solve for L and convert to mL.

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