The wheel of an adult's bicycle has diameter 26 in. The wheel of a child's bicycle has diameter 18 in. To the nearest inch, how much farther does the larger bicycle wheel travel in one revolution than the smaller bicycle wheel?
to do this, we calculate both of the circles' circumference. the bigger circle has diameter of 26 in, while the smaller has diameter of 18 in.
now recall that the circumference of a circle is given by
C = 2*π*r
or given the diameter,
C = π*d
where
π = constant equal to 3.14
r = radius
d = diameter
substituting,
bigger circle:
C = π*d = 3.14*26 = 81.64 in
smaller circle:
C = π*d = 3.14*18 = 56.52 in
then we subtract:
81.64 - 56.52 =
25.12 in
hope this helps~ :)
the endpoints of a diameter of a circle are A(2,1) and B(5,5). Find the area of the circle in terms of pie.
To find out how much farther the larger bicycle wheel travels in one revolution than the smaller bicycle wheel, we need to compare the circumferences of the two wheels.
The formula for the circumference of a circle is C = πd, where C is the circumference and d is the diameter.
For the adult's bicycle wheel:
C1 = πd1
C1 = π(26)
For the child's bicycle wheel:
C2 = πd2
C2 = π(18)
To find the difference in distance traveled in one revolution, we subtract the smaller circumference from the larger circumference:
Difference = C1 - C2
Difference = π(26) - π(18)
Now, to get the answer, we can calculate the numerical value of this expression:
Difference ≈ 3.14(26) - 3.14(18)
Difference ≈ 81.64 - 56.52
Rounding to the nearest inch, the larger bicycle wheel travels approximately 25 inches farther in one revolution than the smaller bicycle wheel.