Pre-Calculus

posted by .

2secx= 3cscx

  • Pre-Calculus -

    Are we solving ?
    if so, then

    2/cosx = 3/sinx
    2sinx = 3cosx
    sinx/cosx = 3/2
    tan x = 3/2 = 1/5
    x = 56.3° or 236.3°

    change the setting on your calculator to radians if you need the angles in radians

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Pre-Calculus/Calculus

    I am too embarassed to ask this Calculus (really pre-calculus) question in tutoring, because I know I should know. Is the inverse of f(x)=3x-1 actually f(x)=1/3x+1?
  2. Pre-Calculus

    I am in Honors Pre-Calculus and am having a hard time understanding my teacher. I feel so stupid. Does anyone have any suggestions on a website that might give me some insight into what I am doing wrong?
  3. Pre Calculus

    Pre Calculus why is sin(-20)/cos 380 equal to tan (-200)
  4. calculus

    Did I do this problem right? Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x
  5. Pre-Calculus

    I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) …
  6. Precalculus

    I'm trying to verify the identity: (sin^2 x)/(2)= (secx-1)/(2secx)
  7. MATH

    √5sec²x-2secx=5 i have to solve this equation on the interval [0, 2π).
  8. math

    prove that cosx(tanx+2)(2tanx+1)=2secx+5sinx
  9. Math

    Solve 3cosx+1=2secx
  10. Finite Math

    Fifty percent of students enrolled in calculus class have previously taken pre-calculus. Thirty percent of these students received an A for the calculus class, whereas twenty percent of the other students received an A for calculus. …

More Similar Questions