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Light of wavelength 600 nm illuminates a diffraction grating. The second-order maximum is at angle 39.1°.

How many lines per millimeter does this grating have?

  • Physics -

    Strictly speaking, it depends upon the angle of incidence. Assume it is zero degrees (normal).

    Then use the grating equation. Let d be the groove spacing.

    n*(lambda) = d sin(theta)

    In your case,
    lamda (the wavelength) = 600*10^-9 m
    n = 2
    sin(theta) = 0.6307

    Solve for d in meters.

    Lines per mm = 1000/d(meters)

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