posted by Anonymous .
Find the absolute maximum value and the absolute minimum value, if any, of the function.
g(x) = -x(^2) + 2 x + 9
g'(x) = -2x + 2
This is zero when x = 1.
The second derivative, -2, is negative there, so g(1) is a maximum. The value there is 10.
There is no absolute minimum. The function is an upside-down parabola that goes to minus infinity at large and small x.
In google type:
functions graphs online
When you see list of results click on:
When page be open in blue recatacangle type:
-x^2 + 2 x + 9
In Display properties set:
Range y-axis from -7 to 13
Then click option Draw
You will see graph of your function.