a laundry room is shaped like a rectangle. the area of the room is 6 square yards. the perimeter is 10 yards. The room is longer than it is wide. How wide is the room? How long it the room?

Have you tried 2 x 3?

By the way, what is Fher?

Arect = length x width

So you find different factors of the area and you should be able to answer the question competently. As long as you communicate well you might even get extra marks for 'alternate answers'

To find the dimensions of the laundry room, we will use the given information about the area and perimeter.

Let's denote the width of the room as 'w' and the length as 'l'.

We are given that the area of the room is 6 square yards, so we can set up the equation:

Area = Length * Width

6 = l * w ---(Equation 1)

We are also given that the perimeter of the room is 10 yards, which can be expressed as:

Perimeter = 2 * (Length + Width)

10 = 2 * (l + w) ---(Equation 2)

From Equation 2, we can simplify it to:

5 = l + w ---(Equation 3)

Now we have a system of two equations (Equation 1 and Equation 3) that we can solve simultaneously to find the values of 'w' (width) and 'l' (length).

Using Equation 3, we can rewrite it as:

l = 5 - w

Now, substitute the value of 'l' into Equation 1:

6 = (5 - w) * w

Distribute and simplify:

6 = 5w - w^2

Rearrange the equation:

w^2 - 5w + 6 = 0

Now we have a quadratic equation. We can solve it by factoring or using the quadratic formula.

Factoring, we get:

(w - 2)(w - 3) = 0

Setting each factor equal to zero:

w - 2 = 0 --> w = 2
w - 3 = 0 --> w = 3

Therefore, there are two possible solutions for the width: w = 2 yards or w = 3 yards.

If we substitute these values back into Equation 3, we find:

For w = 2:
l = 5 - 2 = 3 yards

For w = 3:
l = 5 - 3 = 2 yards

Since the room is longer than it is wide, the width cannot be longer than the length. Therefore, the width of the room is 2 yards and the length is 3 yards.