An unknown material absorbs 1,930 J of heat when it changes from 25 °C to 35°C. The sample weighs 500g. What is the specific heat of this material?
Would you use q/mass*change in T= c
so 1930J/(500g*10degC)=.386J/degC?
Yes. That looks right to me.
To find the specific heat of a material, you can use the equation:
q = mcΔT
Where:
q is the heat absorbed or released by the material
m is the mass of the material
c is the specific heat of the material
ΔT is the change in temperature
In this case, the heat absorbed by the material (q) is given as 1,930 J, the mass (m) is given as 500 g, and the change in temperature (ΔT) is 35°C - 25°C = 10°C.
Substituting these values into the equation:
1,930 J = (500 g) * c * 10°C
To solve for c (the specific heat), divide both sides of the equation by (500 g * 10°C):
c = 1,930 J / (500 g * 10°C)
Now you can calculate the specific heat:
c = 0.386 J/g°C
Therefore, the specific heat of this unknown material is 0.386 J/g°C.