math
posted by Robbie .
can someone help explain how to do this?
allen has nickels dimes and quarters in his pocket. the number of nickels is 1 more than twice the number of quarters. the number of dimes is 1 less than the number of quarters. if the value of change in his pocket is 85 cents, how many of each coin does he have?

number of quarters = x
number of nickels = 2x+1
number of dimes = x1
now use the "value" of those coins to get
25x + 5(2x+1) + 10(x1) = 85
should be pretty easy to solve
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