Algebra IIPlease check my calculation
posted by Sheila .
Find center, vertices, covertices and foci for the following;
(x3(^2/49 + (y4)^2/4 = 1
Center would be (3,4)
A=7
b=2
Vertices would be found this way:
(h+a,k)
(37,4)
(3+7,4)
Vertices = (4,4)
(10,4)
Covertices
(h,k+b)
(3,42)
(3,4+2)
Covertices=(3,2)
(3,6)
If ound "c" by 494 = c^2
45=c^2
3sqrt(5)=c
6.7=c
Foci =(h+c,k)
(36.7,4)
(3+6.7,4)
Covertices=(3.7,4)
(9.7,4)or left in radical it would be: 3 (3sqrt5),4
3+(3sqrt5),4
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