Algebra II-Please check my calculation

posted by .

Find center, vertices, co-vertices and foci for the following;
(x-3(^2/49 + (y-4)^2/4 = 1
Center would be (3,4)
A=7
b=2
Vertices would be found this way:
(h+-a,k)
(3-7,4)
(3+7,4)
Vertices = (-4,4)
(10,4)
Co-vertices
(h,k+-b)
(3,4-2)
(3,4+2)
Co-vertices=(3,2)
(3,6)

If ound "c" by 49-4 = c^2
45=c^2
3sqrt(5)=c
6.7=c
Foci =(h+-c,k)
(3-6.7,4)
(3+6.7,4)
Co-vertices=(-3.7,4)
(9.7,4)or left in radical it would be: 3- (3sqrt5),4
3+(3sqrt5),4

  • Algebra II-Please check my calculation -

    I agree with all your answers.

  • Algebra II-Please check my calculation -

    Thank you

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra 2 Honors- Ellipses

    for my homework problem i have the equation: (x^2/16) + (y^2/4) = 1 I need to find out the center, the vertices, co- vertices and the Foci. I have trouble knowing how to find them, so if you can please explain them. Thank you.
  2. Algebra 2 Honors- Ellipses REAL ONE

    for my homework problem i have the equation: (x^2/16) + (y^2/1) = 1 I need to find out the center, the vertices, co- vertices and the Foci. I have trouble knowing how to find them, so if you can please explain them. Thank you.
  3. Pre-Calculus

    Find the coordinates of the center, the foci, the vertices, and the equations of the asymptotes of the graph of the equation: (x+1)^2/2-y^2/8=1. Center: (-1,0) foci:(-1+/-sqrt1, 0) vertices: (-1+/-sqrt2, 0) equations of the asymptotes: …
  4. Pre-calculus

    For the ellipse with equation 5x^2+64y^2+30x+128y-211=0, find the cooridinates of the center, foci, and vertices. Then, graph the equation. my answer is: coordinates of center: (-3,1) foci:(-11,-1) and (4.7,-1) vertices: (-11,-1) (5,-1) …
  5. Algebra 2

    Choose the equation that best represents an ellipse for the given foci and co-vertices. 1. foci (+-2, 0) co-vertices (0, +-4) 2. foci (+-3, 0) co-vertices (0,+-6) 3. foci (0, +-3) co-vertices (+-5, 0) Choose the equation for the hyperbola …
  6. Math

    Find the center, vertices, foci, and eccentricity of the ellipse. 9x^2 + 4y^2 - 36x + 8y + 31 = 0 I know the center is (2,-1) For the vertices I had (3,-1)(1,-1) and the foci (3.8,-1)(.20,-1) and e = 1.80 but I think these are wrong.
  7. Algebra II-Please check

    I'm sorry the computer jammed on an earlier post and I couldn't do anything-so here is the problem I need asistance with Please check and offer advice-I'm NOT SURE IF I USED CORRECT FORMULAS-thank you the problem is List the center, …
  8. algebra 2

    Graph the equation. Identify the vertices, co-vertices, and foci of the ellipse. 64x^2+16y^2=1024 This is what i have so far vertices (0,8)(0,-8) foci(0,4√3),(0,-4√3)
  9. precalc

    For each: a) Identify the ellipse as horizontal or vertical b) Give the coordinates of 1) The center 2) The major vertices 3) The minor vertices 4) The foci 1) [(x+4)2/64] + (y2/100) = 1 2) [(x-1)2 / 36] + [(y+3)2 / 25] = 1
  10. precalc

    Find the standard form equation for each ellipse described. 1) Major vertices at (0, 3) and (0, -3), minor vertices at (2, 0) and (-2, 0) 2) Major vertices at (7, 0) and (-7, 0), foci at (5, 0) and (-5, 0) 3) Minor vertices at (-2, …

More Similar Questions