math
posted by fernando .
the dimensions of a rectangle are such that its length is 3 inches more than its width. if the length were double and if the width were decreased by 1 inch, the area would be increased by 66inches ^2. What are the length and width of the rectangle?

Let w = width and w+3 = length.
2(w+3)(w1)  w(w+3) = 66
Solve for w, then w+3.
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