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When 90 kJ is removed from a 2-kg copper bar its temperature drops from 200 degrees celcius to 85 degrees celcius what is the specific heat of the iron?

  • science -

    Q = M*C*(delta T)

    Solve for C, with

    deltaT = -115 C
    Q = -90 kJ
    M = 2.0 kg

  • science -

    0.391

  • science -

    0.39 kJ/kg degree C

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