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A cannon tilted up at a 26.0 degree angle fires a cannon ball at 78.0 m/s from atop a 12.0 m-high fortress wall. What is the ball's impact speed on the ground below?

  • physics -

    u = constant horizontal speed = 78 cos 26

    Vi = initial up speed = 78 sin 26

    v = Vi - g t

    h = 12 + Vi t - 4.9 t^2

    at ground, h = 0
    4.9 t^2 -Vi t - 12 = 0

    solve for t, time in air
    then use that t so solve for v at t in v=Vi -9.8 t

    then impact speed = sqrt(u^2+v^2)

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