A resultant force of 25 Newton acts on mass of 0.5 kg standing from rest.
find: a) the acceleration in m/s square
b) the final velocity after 20 seconds
c) the distance moved in meter
Please help me with the answers
To find the answers to these questions, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
a) The acceleration (a) can be found using the formula:
a = F/m
where F is the resultant force and m is the mass.
In this case, the resultant force (F) is 25 Newton and the mass (m) is 0.5 kg.
Plugging in the values, we have:
a = 25 N / 0.5 kg = 50 m/s^2
Therefore, the acceleration is 50 m/s^2.
b) To find the final velocity (v) after a certain time, we can use the equation:
v = u + at
where u is the initial velocity, a is the acceleration, and t is the time.
In this case, the object starts from rest, so the initial velocity (u) is 0 m/s and the time (t) is given as 20 seconds.
Plugging in the values, we have:
v = 0 m/s + (50 m/s^2)(20 s) = 1000 m/s
Therefore, the final velocity after 20 seconds is 1000 m/s.
c) To find the distance moved (d), we can use the equation:
d = ut + (1/2)at^2
where u is the initial velocity, a is the acceleration, and t is the time.
In this case, the object starts from rest, so the initial velocity (u) is 0 m/s and the time (t) is given as 20 seconds. We already calculated the acceleration (a) as 50 m/s^2.
Plugging in the values, we have:
d = 0 m/s * 20 s + (1/2)(50 m/s^2)(20 s)^2 = 0 + 1/2 * 50 * 400 = 10000 m
Therefore, the distance moved in 20 seconds is 10000 meters.