posted by Nabil .
the 20 kg block is at the top of a 10 m long inclined plane. The block starts from rest and slides without friction down the length of the incline. The block is 5 m high.
1) Determine the gravitational potential energy of the block at the top of the incline.
Will PE = mgh = 20 * 9.8 * 5 work?
2) Determine the kinetic energy of the block when it reaches the bottom of the incline
Will KE = 1/2 mv^2
980 = 1/2 (20) v^2 solve for v work?
physics - bobpursley, Sunday, March 20, 2011 at 8:12pm
I am uncertain of the height on 1). You said the block is 5 m high? Did you mean the inclined plane?
2) again, same issue.
physics - Nabil, Sunday, March 20, 2011 at 9:50pm
Sorry. Yes, the inclined plane is 5 m high.
so will the PE and KE formulas work?
2. There is no friction; therefore, KE = PE = 980 J.