ethan had $8 more than dakota. ethan then gave 1/4 od hia money to dakota. the ratio of money ethan had to the money dakota had then became 5:7. howmuch money did ethan give to dakota

took me 7 years to figure this out... but the answer in $10

$10

noice

To solve this problem, we need to break it down into steps:

Step 1: Set up the initial equation
Let's assume that Dakota initially had x dollars.
Given that Ethan had $8 more than Dakota, Ethan would have x + $8 dollars.

Step 2: Calculate the amount Ethan gave to Dakota
Ethan gave 1/4 of his money to Dakota. Since Ethan had x + $8 dollars, the amount he gave would be (1/4) * (x + $8) = $((x + 8) / 4).

Step 3: Calculate the new ratio of money
After Ethan gave money to Dakota, the ratio of money Ethan had to the money Dakota had became 5:7. This means that (x + $8) / $((x + 8) / 4) = 5/7.

Step 4: Solve for x
Cross-multiplying the equation ((x + 8) / $((x + 8) / 4)) = 5/7, we have (7)(x + 8) = 5(x + $8).
Simplifying, 7x + 56 = 5x + 40.
Subtracting 5x from both sides, 2x + 56 = 40.
Subtracting 56 from both sides, 2x = -16.
Finally, dividing by 2, x = -8.

Step 5: Calculate the amount Ethan gave to Dakota
To find the amount of money Ethan gave to Dakota, we substitute x = -8 into the equation (1/4) * (x + $8):
(1/4) * (-8 + $8) = (1/4) * (0) = $0.

Therefore, Ethan gave $0 to Dakota.

E = D + 8

.75E/(D+.25E) = 5/7

Substitute D+8 for E in second equation and solve for D. Insert that value into the first equation and solve for E. Check by inserting both values into the second equation.

E/4 = ?