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What is the molarity of ZnCl2(aq) that forms when 15.4 g of zinc completely reacts with CuCl2(aq) according to the following reaction? (Assume a final volume of 175 mL.)


Zn(s) + CuCl2(aq) --> ZnCl2(aq) + Cu(s)

I got the moles of Zn but don't know what to do with it

thanks

  • chem -

    moles Zn = 15.4 g Zn/atomic mass Zn.
    Convert moles Zn to moles ZnCl2 using the coefficients in the balance equation.
    Then M ZnCl2 = moles ZnCl2/L soln.

  • chem -

    Thanks!

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