Post a New Question


posted by .

What must be the orbital speed of a satellite in a circular orbit 740 km above the surface of the earth?

  • Physics -

    The distance from the center of the earth will be
    R = 740 + Re
    = 6380 = 7120 km = 7.12*10^6 m

    GMm/R^2 = mV^2/R

    V = sqrt(GM/R)
    G is the universal gravity constant and M is the mass of the earth. Solve for V

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question