Physics

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What must be the orbital speed of a satellite in a circular orbit 740 km above the surface of the earth?

  • Physics -

    The distance from the center of the earth will be
    R = 740 + Re
    = 6380 = 7120 km = 7.12*10^6 m

    GMm/R^2 = mV^2/R

    V = sqrt(GM/R)
    G is the universal gravity constant and M is the mass of the earth. Solve for V

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