Zinc metal reacts with hydrochloric acid to produce zinc (II) chloride and hydrogen gas. what volume (in mL) of 2.0M HCl is required to dissolve a 10.0g piece of zinc?

Just follow te steps.

http://www.jiskha.com/science/chemistry/stoichiometry.html

To find the volume (in mL) of 2.0 M HCl required to dissolve a 10.0 g piece of zinc, we can use stoichiometry and molar concentration.

1. Write the balanced equation for the reaction:
Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g)

2. Determine the molar mass of zinc (Zn):
Zn: 65.38 g/mol

3. Convert the mass of zinc to moles:
moles of Zn = mass of Zn / molar mass of Zn
moles of Zn = 10.0 g / 65.38 g/mol
moles of Zn = 0.153 mol

4. Use stoichiometry to find the moles of HCl required:
From the balanced equation, we can see that the ratio of Zn to HCl is 1:2. This means that for every 1 mole of Zn, we need 2 moles of HCl.
moles of HCl required = 2 * moles of Zn
moles of HCl required = 2 * 0.153 mol
moles of HCl required = 0.306 mol

5. Calculate the volume of HCl required using molarity (M) and the equation:
Molarity (M) = moles of solute / volume of solution (in L)

Let's convert from moles to liters:
volume of HCl required (in L) = moles of HCl required / molarity of HCl

volume of HCl required (in L) = 0.306 mol / 2.0 mol/L
volume of HCl required (in L) = 0.153 L

6. Convert the volume of HCl from liters to milliliters:
volume of HCl required (in mL) = volume of HCl required (in L) * 1000 mL/L
volume of HCl required (in mL) = 0.153 L * 1000 mL/L
volume of HCl required (in mL) = 153 mL

Therefore, you would need 153 mL of 2.0 M HCl to dissolve a 10.0 g piece of zinc.

To determine the volume of 2.0M HCl required to dissolve 10.0g of zinc, we can follow these steps:

Step 1: Write down the balanced chemical equation for the reaction:
Zn + 2HCl → ZnCl₂ + H₂

Step 2: Calculate the amount of zinc (in moles) used:
Given mass of zinc = 10.0g
Molar mass of zinc (Zn) = 65.38 g/mol

Number of moles of zinc = mass / molar mass
Number of moles of zinc = 10.0g / 65.38 g/mol ≈ 0.153 mol

Step 3: Identify the stoichiometric ratio between zinc and hydrochloric acid from the balanced equation:
From the balanced equation, we see that 1 mole of zinc reacts with 2 moles of HCl.

Step 4: Calculate the amount of HCl (in moles) required:
Number of moles of HCl = 2 x Number of moles of zinc
Number of moles of HCl = 2 x 0.153 mol = 0.306 mol

Step 5: Calculate the required volume of 2.0M HCl:
Molarity (M) = moles / volume (L)

Rearranging the equation, we get:
Volume (L) = moles / Molarity

Volume (L) = 0.306 mol / 2.0 mol/L = 0.153 L

Step 6: Convert the volume from liters to milliliters:
1 L = 1000 mL

Volume (mL) = 0.153 L x 1000 mL/L = 153 mL

Therefore, 153 mL of 2.0M HCl is required to dissolve a 10.0g piece of zinc.