Statistics
posted by chalulu .
Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gender of any other children. Find the probability of exactly eight in ten births.

Use the binomial probability function. If you use a binomial probability table, this problem will be easily solved. In most tables, you will need x, n, and p. x = 8, n = 10, and p = .5 (look up the probability in the table using those values).
I hope this will help. 
16

10C8 (0.5)^8 x (0.5)^2 = 0.044
n=10 , x=8 , p = 0.5
out of 10, you choose 8
p of getting boys = 0.5
p of getting girls = 0.5
otherway, get exactly 2 girls
10C2 (0.5)^10 = 0.044