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Diff eqn- IVP

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A particle moves on the x-axis with an acceleration, a=(6t-4)ms⁻1. Find the position and velocity of the particle at t=3 , if the particle is at origin and has a velocity of when t=0

  • Diff eqn- IVP -

    This is an IVP (initial value problem).

    x"(t)=(6t-4) ms-2 ....(1)

    "...if the particle is at origin and has a velocity of ? when t=0."

    Integrate (1) with respect to t to find x'(t) and x(t). Do not forget the integration constants at each integration.

    Use the initial conditions
    x(0)=0 and x'(0)=(???)
    to find C1 and C2 (int. constants).
    When C1 and C2 are known, evaluate
    x(3) and x'(3) as required.

  • Diff eqn- IVP -

    thanzz again

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