posted by Abby .
Determine the volume of 0.240 M KOH solution required to neutralize each of the following samples of sulfuric acid. The neutralization reaction is shown below.
H2SO4(aq) + 2 KOH(aq)--> K2SO4(aq) + 2 H2O(l)
(a) 26 mL of 0.240 M H2SO4
How many moles H2SO4 do you have. M x L = moles.
Using the coefficients in the balanced equation, convert moles H2SO4 to moles KOH. Note that 1 mole H2SO4 = 2 mole KOH.
Now M KOH = moles KOH/L KOH. Solve for L KOH.