Algebra 2
posted by Esther .
Subtract. Simplify by removing a factor of 1 when possible.
(10bf)/(b^2f^2)(bf)/b+f)
Thank you for your help

hint
b^2f^2 = (bf)(b+f) 
So, is the answer (bf)(b+f)? which I think goes at the bottom as a fraction, and if it does, what is the number that goes on top?
However, I could be wrong, can you please help me understand? Thank you. 
(10bf)/(b^2f^2)(bf)/b+f)
=(10bf)/((b+f))(bf))  (bf)/(b+f)
Now multiply second term top and bottom by (bf) to get a common denominator
(10bf)/((b+f))(bf))  (bf)(bf)/((b+f)(bf))
You can take it from here.
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