find the number of grams of ice, at 0 degrees celcius that could be melted by the addition of 3.6 kilojoules of heat.
Wouldn't that be worked the same way as your other ice post?
http://www.jiskha.com/display.cgi?id=1299813598
how do you find the heat fusion?
It's in the post?
http://www.jiskha.com/display.cgi?id=1299813598
To find the number of grams of ice that can be melted by adding 3.6 kilojoules of heat, we need to use the concept of heat of fusion and the specific heat capacity of ice. Here's how you can calculate it:
1. Convert the given heat energy from kilojoules to joules:
1 kilojoule = 1000 joules
Therefore, 3.6 kilojoules = 3.6 × 1000 = 3600 joules
2. Determine the heat of fusion for ice:
The heat of fusion of ice is 334 J/g. This value represents the amount of heat required to convert one gram of ice at 0°C to water at 0°C.
3. Calculate the number of grams of ice that can be melted:
Divide the heat energy (in joules) by the heat of fusion (in joules/gram):
Number of grams of ice = Heat energy (joules) / Heat of fusion (joules/gram)
Number of grams of ice = 3600 joules / 334 J/g ≈ 10.78 grams
Therefore, approximately 10.78 grams of ice at 0 degrees Celsius can be melted by the addition of 3.6 kilojoules of heat.