How many grams of Ammonia, NH3 can be made from 250. grams of N2(g) ?
( first Balance the equation)
N2 (g) + H2 (g) > NH3 (g)
Well, first let's balance the equation:
N2 (g) + 3H2 (g) → 2NH3 (g)
Now, let's do some math! Using the balanced equation, we see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. So we need to convert grams of N2 to moles using its molar mass (28.02 g/mol).
250 grams of N2 can be converted to moles by dividing by the molar mass:
250 g / 28.02 g/mol = 8.92 moles of N2.
Since N2: NH3 has a 1:2 mole ratio, this means that 8.92 moles of N2 will produce twice as many moles of NH3, which is 17.84 moles.
Now, we need to convert moles of NH3 to grams using its molar mass (17.03 g/mol):
17.84 moles of NH3 × 17.03 g/mol = 304 grams of NH3.
So, approximately 304 grams of NH3 can be made from 250 grams of N2. Just remember, these calculations are assuming a theoretical yield and may not account for any losses during the reaction.
To balance the equation:
N2(g) + 3H2(g) → 2NH3(g)
Now, we can use the balanced equation to find out how many grams of ammonia can be made from 250 grams of nitrogen gas (N2).
According to the equation, 1 mole of N2 reacts to produce 2 moles of NH3. The molar mass of N2 is 28.02 g/mol, so we need to convert 250 grams of N2 into moles.
First, calculate the number of moles of N2:
Number of moles = mass / molar mass
Number of moles = 250 g / 28.02 g/mol ≈ 8.92 mol
Since the ratio between N2 and NH3 is 1:2, we can convert moles of N2 to moles of NH3:
Number of moles of NH3 = 2 × Number of moles of N2
Number of moles of NH3 = 2 × 8.92 mol = 17.84 mol
Now, we can convert the moles of NH3 back into grams:
Mass of NH3 = Number of moles × molar mass
Mass of NH3 = 17.84 mol × 17.03 g/mol ≈ 303.93 g
Therefore, approximately 303.93 grams of NH3 can be made from 250 grams of N2.
To balance the equation, we need to make sure that the number of each type of atom is the same on both sides of the equation.
The unbalanced equation is:
N2 (g) + H2 (g) → NH3 (g)
First, let's balance the nitrogen atoms. There are two nitrogen atoms on the left side (N2), so we need two ammonia molecules (NH3) on the right side.
N2 (g) + H2 (g) → 2NH3 (g)
Next, let's balance the hydrogen atoms. There are four hydrogen atoms on the right side (2NH3), so we need to add two hydrogen molecules (H2) on the left side.
N2 (g) + 3H2 (g) → 2NH3 (g)
Now that the equation is balanced, we can calculate the amount of ammonia (NH3) that can be made from 250 grams of nitrogen gas (N2).
The balanced equation tells us that 1 mole of nitrogen gas (N2) reacts to form 2 moles of ammonia (NH3).
To calculate the number of moles, we need to divide the given mass of N2 (250 grams) by its molar mass.
The molar mass of N2 is:
N2 = 2 nitrogen atoms × 14.01 grams/mole = 28.02 grams/mole
Now, we can calculate the number of moles of N2:
moles of N2 = mass of N2 / molar mass of N2
moles of N2 = 250 grams / 28.02 grams/mole ≈ 8.92 moles
According to the balanced equation, 1 mole of N2 produces 2 moles of NH3. So, the number of moles of NH3 that can be made from 8.92 moles of N2 is:
moles of NH3 = 2 × moles of N2
moles of NH3 = 2 × 8.92 moles = 17.84 moles
Lastly, we can calculate the mass of NH3 using its molar mass:
The molar mass of NH3 is:
NH3 = (1 nitrogen atom × 14.01 grams/mole) + (3 hydrogen atoms × 1.01 grams/mole) = 17.03 grams/mole
Now, we can calculate the mass of NH3:
mass of NH3 = moles of NH3 × molar mass of NH3
mass of NH3 = 17.84 moles × 17.03 grams/mole ≈ 304 grams
Therefore, approximately 304 grams of ammonia (NH3) can be made from 250 grams of nitrogen gas (N2).
Just follow the steps of the link below.
http://www.jiskha.com/science/chemistry/stoichiometry.html