posted by candy .
0.3g of clotrimazole (C22H17ClN2) was dissolved in 80ml of anhydrous acetic acid. This was titrated with 0.1M perchloric acid using 0.3ml of naphtholbenzein as indicator until the colour changes from brownish-yellow to green.
1ml of 0.1M perchloric acid is equivalent to 34.48mg of clotrimazole (C22H17ClN2).
1st titration= A ml of 0.1M perchloric acid was used.
2nd titration= B ml of 0.1M perchloric acid was used.
How do I calculate the % of clotrimazole?
A mL x (34.48 mg cmpd/1mL) = ??mg cmpd. Convert to grams, then
(grams/0.3)*100 = %
B mL is done the same way.