Chemistry

posted by .

A student titrates 0.100M KOH into 50.00 ml of weak acid HX. The pH of the solution is 4.25 after 20.00 ml of the base has been added, and equivalence point is reached when 40.00 ml of the base is added.


1. What is the concentration of the acid, HX ?

2. What is the Ka value of acid HX?

  • Chemistry -

    HX + NaOH ==> NaX + H2O
    1. mL x M = mL x M
    2. 20 mL is at the half-way point to the equivalence point and pH = pKa; therefore, pKa = 4.25.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    A student titrates HCl with 0.0125M KOH. Starting with 50.00 ml of the acid it takes 40.0 ml of base to reach equilavence point. A. What is the concentration of the HCl?
  2. Chemistry

    A student titrates HCl with 0.0125M KOH. Starting with 50.00 ml of the acid it takes 40.0 ml of base to reach equilavence point. A. What is the concentration of the HCl?
  3. Chemistry

    A student titrates 0.025 M KOH into 50.00 ml of a solution of unknown weak acid HA. Equivalence point is reached when 30.00 ml of the KOH has been added. After 15.00ml of the KOH has been added the pH of the mixture is 3.92. A. What …
  4. Chemistry

    A student titrates 0.025 M KOH into 50.00 ml of a solution of unknown weak acid HA. Equivalence point is reached when 30.00 ml of the KOH has been added. After 15.00ml of the KOH has been added the pH of the mixture is 3.92. A. What …
  5. Chemistry

    A student titrates HCl with 0.0125M KOH. Starting with 50.00 ml of the acid it takes 40.0 ml of base to reach equilavence point. A. What is the concentration of the HCl?
  6. Chemistry

    A student titrates 0.100M KOH, potassium hydroxide, into 50.0ml of 0.10M HCOOH, formic acid (Ka=1.8 x 10^-4. What is the pH of the mixture after 25.0ml of the KOH has been added
  7. Chemistry

    A student titrates 0.100M KOH, potassium hydroxide, into 50.0ml of 0.10M HCOOH, formic acid (Ka=1.8 x 10^-4. What is the pH of the mixture after 25.0ml of the KOH has been added
  8. AP Chemsitry

    A solution of an unknown monoprotic weak acid was titrated with 0.100 M NaOH. The equivalence point was reached when 37.48 ML of base had been added. From a second buret, exactly 18.74 of 0.100 M HCl were added to the titration solution. …
  9. AP Chemistry

    A solution is prepared by titrating a 100.0 mL sample of 0.10 M HF (Ka = 7.2 × 10-4) with 0.10 M NaOH a. Does the solution contain a strong acid with a strong base, a strong acid with a weak base, a weak acid with a strong base, or …
  10. AP Chemistry

    A solution is prepared by titrating a 100.0 mL sample of 0.10 M HF (Ka = 7.2 × 10-4) with 0.10 M NaOH a. Does the solution contain a strong acid with a strong base, a strong acid with a weak base, a weak acid with a strong base, or …

More Similar Questions