Trigonometry
posted by Justin .
F(X) = 2x^35x^219x+1 / x^29....I need the vertical asymptote, horizontal asymptote and the slant asymptote...please help!

Vertical asymptote: denominator = 0, so: x^2  9 = 0
Horizontal: lim x>(infinity) f(x)
Since the degree of nominator is higher than the denominator, then the horizontal asymptote does not exist.
Slant: use long division method to find the quotient. That quotient is the slant asymptote
In this case: divide 2x^35x^219x+1 with x^29 
k(x)= x^42x +7/x^29