# Chem- PLZ HELP!

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Consider 100g of 5.5% (mass) solution of NaNO3. Complete the following table, before calculating molarity, molality and mole fraction of NaNO3.

Solute(NaNO3)|Solvent(H2O|Soln
Mass(g) 100g

Moles ----

RefInfo 85g/mol 18.02g/mol

Density=1.00g/mol (This goes under "soln" as reference info).

Ok well I attempted to make a table. I have to fill it in. Can anyone help me fill it out plz?

• Chem- PLZ HELP! -

Ok that looks wrong.

100g should be under solution for the mass, 18.02g/mol for the solvent of H2O and 85g/mol for the solute of NaNO3. I have to find mass of solute and solvent and the moles of solute and solvent. Pls help anyone!

• Chem- PLZ HELP! -

I can't make out some of it but I can get you started and you can fill in the missing parts.
100 g NaNO3 solution that is 5.5% w/w.
That is NOT 100 g NaNO3, that is 100 g of the solution.
5.5% w/w means 5.5 g NaNO3/100 g solution.

So mass solute = 5.5 grams.
moles solute = 5.5/molar mass NaNO3.
mass solution = 100 g
mass solute = 5.5
mass solvent (H2O) = 100-5.5 = ??
moles solvent(H2O) = g solvent/molar mass solvent.

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