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an aqueous solution was prepared by dissolving 1438.0g of a nonelectrolyte in 469.0g of water at 25*c. the Vapor pressure of the resulting solution was found to be 20.5 torr. what is the molar mass of the unknown compound? the vapor pressure of the water at 25*c is 23.76torr.

  • chemestry -

    delta Psoln = Xsolute*PoH2O
    23.76-20.5 = Xsolute*Psolvent
    Solve for Xsolute.
    Then
    nsolute/(n solute + n H2O) = Xsolute
    n H2O = 469/molar mass H2O.
    Solve for n solute, then
    n = grams/molar mass and rearrange to
    molar mass = grams/n. Solve for molar mass.

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