a 64.0L gas tank is filled at 6.00C. the next day the temperature gets up to 27.00C how much gas (octance) voerflows?
To determine how much gas overflows from the 64.0L gas tank as the temperature rises from 6.00°C to 27.00°C, we need to consider the effect of temperature on the volume of the gas. We can use Charles's Law to calculate the change in volume.
According to Charles's Law, the volume of a gas is directly proportional to its temperature when pressure and moles of gas are held constant. Mathematically, it can be expressed as:
V₁/T₁ = V₂/T₂
where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.
Let's plug in the values:
V₁ = 64.0L
T₁ = 6.00°C = 6.00 + 273.15 = 279.15K
T₂ = 27.00°C = 27.00 + 273.15 = 300.15K
Using the formula, we get:
64.0L / 279.15K = V₂ / 300.15K
Now we can solve for V₂:
V₂ = (64.0L / 279.15K) * 300.15K
V₂ ≈ 68.99L
The final volume of the gas is approximately 68.99L. To calculate the overflow, we subtract the initial volume from the final volume:
Overflow = V₂ - V₁
Overflow = 68.99L - 64.0L
Overflow ≈ 4.99L
Therefore, approximately 4.99L of gas (octane) overflows from the gas tank as the temperature rises from 6.00°C to 27.00°C.