# physics

posted by .

A 1460-kg car is being driven up a 10.0 ° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of 497 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W and the normal force FN directed perpendicular to the road surface. The length of the road up the hill is 209 m. What should be the magnitude of F, so that the net work done by all the forces acting on the car is 149 kJ?

• physics -

Fc=mg=1460kg * 9.8N/kg=14308N @ 10deg.

Fp = 14308*sin10 = 2484.56N = Force parallel to the plane downward.

Fv = 14308*cos10 = Ff = .63N = Force perpendicular to the plane and acting downward.

Ff = 497N = Force of friction acting
opposite to the motion.

W = Fn*d = 149000J.
Fn * 209 = 149000,
Fn = 149000 / 209 = 712.92 = Net force.

Fn = Fap - Fp - Ff = 712.92,
Fap - 2484.56 - 497 = 712.92,
Fap - 2981.56 = 712.92,
Fap = 712.92 + 2981.56 = 3695N = Force
applied.

• physics -

CORRECTION:

Fv = 14308*cos10 = 14090.63N = Force perpendicular to the plane and acting
downward.

## Similar Questions

1. ### physics

A 1200-kg car is being driven up a 5.0degrees hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f=524N. A force F is applied to the car by the road and propelsthe car forward. In addition …
2. ### physics

A 1200 kg car is being driven up a 5:0 hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force ~F is applied to the car by the road and propels the car forward. In addition …
3. ### physics

A 1200 kg car is being driven up a 5:0 hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force ~F is applied to the car by the road and propels the car forward. In addition …
4. ### physics

A 1200 kg car is being driven up a 5:0 hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force ~F is applied to the car by the road and propels the car forward. In addition …
5. ### physics hw

A 300. kg roller coaster car is traveling at a constant speed of 15 m/s over a hill with a radius of curvature of 30. m. b. What is the normal force acting on the car at the top of the hill?
6. ### Physics

A 1100-kg car is being driven up a 4.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 518 N. A force is applied to the car by the road and propels the car forward. In addition …
7. ### physics

A 1100-kg car is being driven up a 4.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 518 N. A force is applied to the car by the road and propels the car forward. In addition …
8. ### physics

A 1100-kg car is being driven up a 4.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 518 N. A force is applied to the car by the road and propels the car forward. In addition …
9. ### physics

A 1310-kg car is being driven up a 9.12 ° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of 541 N. A force F is applied to the car by the road and propels the car forward. In addition …
10. ### Physics

A sports car is accelerating up a hill that rises 17.0° above the horizontal. The coefficient of static friction between the wheels and the road is µs = 0.79. It is the static frictional force that propels the car forward. (a) …

More Similar Questions