Math
posted by Hannah .
Find the critical values of P(x)
p(x)= (28+x)(8x/4)
the answer was p=2447x+8xx^2/4
p=x^2/4 + x + 244
p'= x/2 +1 = 0
X=2
My question is, I do not understand how they got 7x + 8x at the beginning. I know (28)(8)=244 but I do not get the rest.
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