Math (Trig)
posted by Meg .
a ferris wheel has a radius of 10m and is one meter above the ground. If the ferris wheel makes 1 revolution every 20 seconds, write an equation that gives the height above the ground of a person on the ferris wheel as a function of time if that person starts (t=0) 1/8th of a rotation away from the bottom most point while moving downwards
please help!!

1 rotation = 2pi
1/8 rotation = 1/8 x 2pi = pi/4
State y as the height difference created from the rotation of the wheel and the bottom of the ferris wheel (not the ground)
height = y + 1
= r  r cos {(2pi/20)t  (pi/4)} +1
= r(1  cos pi{(t/10)  (1/4)}) +1
= 10(1  cos pi{(t/10)  (1/4)}) +1
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