Calculus

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Find the area in the second quadrant bounded by the x-axis and f(x)=sqrt((x^3/8)+1)

  • Calculus-please check -

    is the function meant to be
    f(x)=sqrt(((x^3)/8)+1)
    or
    f(x)=sqrt((x^(3/8))+1)

    In the latter case, the function is not defined in the second quadrant (x<0).

  • Calculus -

    It is supposed to be the first one.
    Sorry for the confusion!!

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