Algebra 1
posted by Ru .
When a plane flies into the wind, it can travel 3000mi in 6 hr. When it flies with the wind, it can travel the same distance in 5 hr. Find the rate of the plane in still air and the rate of the wind.

x = Rate without wind
y = Rate of the wind
T = D/R
6 = 3000/(x  y)
6(x  y) = 3000
6x  6y = 3000
5 = 3000/(x + y)
5(x + y) = 3000
5x + 5y = 3000
Solve simultaneously,
6x  6y = 3000
5x + 5y = 3000
5 *(6x  6y = 3000)= 30x  30y = 15,000
6 *(5x + 5y = 3000)= 30x + 30y = 18,000
30x  30y = 15,000
30x + 30y = 18,000
60x = 33,000
x = 550 rate of the plane in still air
5x + 5y = 3000
x = 550
5(550) + 5y = 3000
2750 + 5y = 3000
5y = 250
y = 50 rate of the wind