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The International Space Station, launched in November 1998, makes 15.65 revolutions around the earth each day in a circular orbit.

Apply Newton's second law to the space station and find its height (in kilometers) above the earth's surface.

  • physics -

    T = 2(Pi)sqrt[r^3/µ)
    T = orbit period in seconds
    r = radial distance of station from Earth's center
    µ = Earth's gravitational constant = 3.986365x10^14m^3/sec.^2
    Solve for r

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