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A dynamite blast at a quarry launches a rock straight upward, and 2.0 s later it is rising at a rate of 15 m/s. Assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b)4.2 s after launch

  • physic -

    v = Vi - gt
    when t = 2, v = 15
    15 = Vi - 9.8*2
    solve for Vi

    then using that Vi solve for v at t = 4.2

  • physic -

    a. is 34.6
    so would b) be v=34.6-(9.8)(4.2)

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