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a .140 kg baseball is dropped from rest from a height of 2.2m above the ground. it rebounds to a height of 1.6 m. what change in the balls momentum occurs when the ball hits the ground

  • physics -

    The momentum change is
    M [V1 -(-V2)] = M(V1 + V2)
    For the two speeds, use
    V1 = sqrt[g*2.2/(2M)] = 8.77 m/s
    V2 = sqrt[g*1.6/(2M)] = 7.48 m/s

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