Algebra II

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We are learning how to solve systems using elimination.

2y - 1 = 3x - y / 5

3x - 4 / 8 = y/4

How would I begin to solve this? I'm mostly unsure of how to simplify the fractions. Thanks so much :)

  • Algebra II -

    2y - 1 = 3x - y/5
    3x - 4/8 = y/4

    First, simplify both equations
    2y - 1 = 3x - y/5
    Multiply both sides by 5
    10y - 5 = 15x - y
    11y - 15x = 5

    3x - 4/8 = y/4
    Multiply both sides by 8
    24x - 4 = 2y
    -2y + 24x = 4

    Multiply by 2 (11y - 15x = 5)
    Multiply by 11 (-2y + 24x = 4)

    22y - 30x = 10
    -22y + 264x = 44

    Add equations
    oy + 234x = 54
    234x = 54
    x = 54/234 = 3/13

    Substitute x = 3/13 in either equation to find y.

    Check your answer.
    If you are correct, y = 10/13

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