Pre-cal/Trig

posted by .

(tan/(1+sec)) + ((1+sec)/tan) = 2csc
(Show all work please.)

  • Pre-cal/Trig -

    I see tangents and secants on the left side, so I suspect to use the identity
    tan^2x + 1 = sec^2x

    LS
    = tanx(1+secx) + (1+secx)/tanx
    = (tan^2x + 1 + 2secx + sec^2x)/(tanx(1+secx))
    = (sec^2x + 2secx + sec^2x)/(tanx(1+secx))
    = (2sec^2x + 2secx)/(tanx(1+secx))
    = 2secx(secx + 1)/(tanx(1+secx))
    = 2secx/tanx
    = (2/cosx)÷(sinx/cosx)
    = (2/cosx)(cosx/sinx)
    = 2/sinx
    = 2cscx
    = RS

    Q.E.D.

  • Pre-cal/Trig -

    y=2sec(1/3x)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct?
  2. Calculus

    could anybody please explain how sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ?
  3. more trig.... how fun!!!!

    if you can't help me with my first question hopw you can help me with this one. sec(-x)/csc(-x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(-x)/csc(-x) = sin(-x)/cos(-x) …
  4. calculus

    find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x …
  5. Math

    We have to solve for the problem below to make sure that it is equivalent to 2csc(x). However, I keep getting 2/2sin(x) and not 2/sin(x), which is what 2csc(x) is. tan(x)/(1+sec(x))+ (1+sec(x))/tan(x)= 2csc(x)
  6. Pre-Cal

    Simplify the expression 1/tan^2x+1 tan^2x+1 = sec^2x = 1/sec^2x I am not sure what 1/sec^2x is equal to
  7. Pre-Cal

    Perform the addition or subtraction. tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the identity 1+tan^2u=sec^2u I do not know what to do at this point.
  8. Calculus 12th grade (double check my work please)

    2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents …
  9. calculus (check my work please)

    Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] …
  10. calculus

    So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a three?

More Similar Questions