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The diagonals of a rhombus ABCD intersect at point E. If the sides of BC is equal to x + 9 and side DC is equal to 5x-2, find x.

How would I set this up-Please give me some direction

All sides of a Rhombus are congruent. Therefore, AB = BC = CD = AD

BC = x + 9
DC = 5x - 2
BC = DC
x + 9 = 5x - 2
4x = 11
x = ?

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