equation of the tangent line to the curve y = 2x²-x+10 at the point (-1,13)

dy/dx = slope = m = 4x-1

m = 4(-1) - 1 = -5
so
y = -5 x + b
find b
13 = -5(-1) + b
b = 8
so
y = -5 x + 8