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A bullet of mass 0.0019 kg moving at 487 m/s embeds itself in a large fixed piece of wood and travels 0.55 m before coming to rest. Assume that the deceleration of the bullet is constant.

What force is exerted by the wood on the bullet?

  • physics -

    Consider the work done by the bullet on the block. It gets turned into heat, and equals the initial kinetic energy of the bullet.

    Force x distance = Initial Kinetic energy

    F = (1/2)M V^2/0.55 = 410 N

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