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The alarm at a fire station rings and a 87-kg fireman, starting from rest, slides down a pole to the floor below (a distance of 3.9 m). Just before landing, his speed is 1.3 m/s. What is the magnitude of the kinetic frictional force exerted on the fireman as he slides down the pole?

  • physics -

    The frictional heat loss F*X equals the loss of mechanical energy

    M g H - (1/2)M*Vfinal^2 = F*X

    M cancels out Solve for F

    H = 3.9 m
    g = 9.8 m/s^2
    Vfinal = 1.3 m/s

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