Precalcus Urgent HELP PLEASE
posted by Anonymous .
Evaluate the function at the indicated value:
g(x) = 3x/3+x
g(a3)=

g(x) = 3x/3+x
g(a3) = 3(a3)/3+(a+3)
g(a3) = 3a+3/3+a+3
g(a3) = 6a/6+a
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