Algebra IIPlease check my solution
posted by Joella .
Solve by elimination methodthanks fro checking my work
2x + 3y= 2 multiply this equation by 2= 4x + 6y = 4
4x2y = 28
4x + 6y = 4
4x 2y = 28
8y = 32
y = 4
2x + 3(4) = 2
2x + 12 = 2
2x + 212
2x = 10
x = 5
solution = (5,4)

you're on the right track but when you tried to subtract the 2 eq you only subtracted the first term, but left the others' signs the same.
It should look like this:
4x+6y=4
4x+2y=28 now add the two eq together and redo the work you did before. if you have more questions just ask! 
when I wrote the 4x 2y = 28
I forgot to put the next step which was 4x + 2y = 28
but isn't the rest of my steps the same still because when I subtracted those they became 8y = 32 and the rest Thanks for respondingI'm not sure if this isn't right stillI think the answer is correct minus the one step I forgot to write 
I think I see where you mistook what I wroteI'm doing the elimination method and subtracting the equations so the new equations were
4x + 6y = 4 after I multiplied first equation by 2
minus 4x 2y = 28 and so the 4x becomes , the 2y becomes positive and the 28 becomes positive, correct
Thank you 
You're right. I'm sorry. When I saw the missed step, I stopped looking at the rest of the work. You are correct.
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